A) \[3.13\times {{10}^{-7}}\]
B) \[3.13\times {{10}^{7}}\]
C) \[3.13\times {{10}^{-10}}\]
D) None of these
Correct Answer: A
Solution :
Here\[{{n}_{p}}=3mol,\,\,{{n}_{r}}=2mol\] \[\therefore \] \[\Delta {{n}_{g}}={{n}_{p}}-{{n}_{r}}=3-2=1\,\,mol\] \[{{K}_{p}}=1.80\times {{10}^{-3}}kPa=1.80\,\,Pa=\frac{1.80}{{{10}^{5}}}bar\] \[=1.80\times {{10}^{-5}}bar\] \[\because \]\[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta {{n}_{g}}}}\] \[{{K}_{c}}=\frac{{{K}_{p}}}{RT}=\frac{1.80\times {{10}^{-5}}bar}{0.0821\,\,L\,\,bar\,\,{{K}^{-1}}\,\,mo{{l}^{-1}}\times 700K}\] \[=3.13\times {{10}^{-7}}\,\,mol\,\,{{L}^{-1}}\]You need to login to perform this action.
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