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Punjab Medical Punjab - MET Solved Paper-2010

  • question_answer
    In an\[AC\]circuit the potential difference V and current i are given respectively by                 \[V=100\sin (100t)volt\]and\[i=100\sin \left( 100t+\frac{\pi }{3} \right)mA\] The power dissipated in the circuit will be

    A) \[{{10}^{4}}W\]                

    B) \[10W\]

    C) \[2.5W\]                             

    D) \[5W\]

    Correct Answer: C

    Solution :

    Voltage amplitude\[{{V}_{0}}=100V\], current amplitude\[{{i}_{0}}=100mA=100\times {{10}^{-3}}A\]and phase difference between\[i\]and\[V\]is\[\phi =\frac{\pi }{3}={{60}^{o}}\]. Now power dissipated is given by \[P=\frac{{{V}_{0}}{{i}_{0}}}{2}\cos \phi =\frac{100\times 100\times {{10}^{-3}}}{2}\times \cos {{60}^{o}}\]                           \[=2.5W\]


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