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Punjab Medical Punjab - MET Solved Paper-2010

  • question_answer
    Dimensions of resistance in an electrical circuit, in terms of dimensions of mass\[M\], of length\[L\], of time\[T\]and of current\[I\], would be

    A) \[[M{{L}^{2}}{{T}^{-3}}{{I}^{-1}}]\]                          

    B) \[[M{{L}^{2}}{{T}^{-2}}]\]

    C) \[[M{{L}^{2}}{{T}^{-1}}{{I}^{-1}}]\]                          

    D) \[[M{{L}^{2}}{{T}^{-3}}{{I}^{-2}}]\]

    Correct Answer: D

    Solution :

    Resistance\[R=\frac{Potential\,\,difference}{Current}=\frac{V}{i}=\frac{W}{qi}\] (\[\because \]Potential difference is equal to work per unit charge) So, dimensions of R \[=\frac{[Dimensions\,\,of\,\,Work]}{[Dimensions\,\,of\,\,charge][Dimensions\,\,of\,\,current]}\]\[=\frac{[M{{L}^{2}}{{T}^{-2}}]}{[IT][I]}=[M{{L}^{2}}{{T}^{-3}}{{I}^{-2}}]\]


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