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Punjab Medical Punjab - MET Solved Paper-2010

  • question_answer
    25 tuning forks are arranged in series in the order of decreasing frequency. Any two successive forks produce 3 beats/s. If the frequency of the first tuning fork is the octave of the last fork, then the frequency of the 21st fork is

    A) \[72Hz\]                              

    B) \[288Hz\]

    C) \[84Hz\]                              

    D) \[87Hz\]

    Correct Answer: C

    Solution :

    If n is the frequency of last fork then frequency of first fork be\[2n\]. So,                 \[2n-(25-1)\times 3=n\] \[\Rightarrow \]               \[n=72Hz\] 21st fork frequency\[=144-(21-1)(3)=84\,\,Hz\]


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