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Punjab Medical Punjab - MET Solved Paper-2010

  • question_answer
    The magnetic field in a region between the poles of an electromagnet is uniform at any time, but its magnitude is increasing at the rate of\[0.02\text{ }T/s\]. A conducting loop is placed in this region, whose plane is perpendicular to the direction of magnetic field. Calculate the emf induced and induced current in the loop. Take cross-section area of loop as \[120c{{m}^{2}}\] and resistance of loop as\[5\Omega \].

    A) \[0.48\,\,V,\,\,0.0096\,\,mA\]

    B) \[0.48\,\,mV,\,\,0.0096\,\,mA\]

    C) \[0.24\,\,mV,\,\,0.048\,\,mA\]

    D) \[0.24\,\,mV,\,\,Zero\]

    Correct Answer: C

    Solution :

    Induced emf         \[e=-\frac{d\phi }{dt}=-A\times \frac{dB}{dt}=-120\times {{10}^{-4}}\times 0.02\] Negative sign tells about the direction (polarity). Also,      \[i=\frac{e}{R}=\frac{0.24}{5}=0.048\,\,mA\]


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