A) \[2s\]
B) \[3s\]
C) \[4s\]
D) None of these
Correct Answer: C
Solution :
From,\[s=ut+\frac{1}{2}a{{t}^{2}}\] Distance covered in\[5s\] \[s=0+\frac{1}{2}\times 10\times {{5}^{2}}=125m\] Distance covered in\[3s\] \[s=0+\frac{1}{2}\times 10\times {{3}^{2}}=45m\] Distance to be covered\[125-45=80m\] From, \[s=ut+\frac{1}{2}a{{t}^{2}}\] \[80=0+\frac{1}{2}\times 10{{t}^{2}}\] \[{{t}^{2}}=\frac{80}{5}=16\] \[t=4s\]
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