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Punjab Medical Punjab - MET Solved Paper-2011

  • question_answer
    A charge of\[5\,\,C\] experiences a force of\[5000\,\,N\]when it is kept in a uniform electric field. What is the potential difference between two points separated by a distance of\[1\,\,cm\]?

    A) \[10\,\,V\]                                         

    B) \[250\,\,V\]

    C) \[1000\,\,V\]                     

    D) \[2500\,\,V\]

    Correct Answer: A

    Solution :

    Electric field\[E=\frac{F}{q}=\frac{5000}{5}=1000\,\,N/C\]                 \[V=Ed\] \[\therefore \]  \[V=1000\times {{10}^{-2}}\]                     \[=10\,\,V\]


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