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Punjab Medical Punjab - MET Solved Paper-2011

  • question_answer
    A body moves with a uniform acceleration\[a\]and zero initial velocity. Another body\[B\]starts from the same point moves in the same direction with a constant velocity\[v\]. The two bodies meet after a time\[t\]. The value of\[t\]is

    A) \[\frac{2v}{a}\]                                

    B) \[\frac{v}{a}\]

    C) \[\frac{v}{2a}\]                                

    D) \[\sqrt{\frac{v}{2a}}\]

    Correct Answer: A

    Solution :

    \[{{s}_{A}}=ut+\frac{1}{2}a{{t}^{2}}\] or            \[{{s}_{A}}=0+\frac{1}{2}a{{t}^{2}}=\frac{1}{2}a{{t}^{2}}\]                 \[{{s}_{B}}=vt\] Given,   \[{{s}_{A}}={{s}_{B}}\]  \[\therefore \] \[\frac{1}{2}a{{t}^{2}}=vt\] or            \[t=\frac{2v}{a}\]


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