A) \[1%\]
B) \[0.5%\]
C) \[2%\]
D) \[4%\]
Correct Answer: C
Solution :
\[I=\frac{1}{2}M{{R}^{2}}\] Take the log on both sides, we have \[\log I=\log M+2\log R\] Differentiating, we get \[\frac{dI}{I}=0+2\frac{dR}{R}\] \[\frac{dI}{I}\times 100=2\left( \frac{dR}{R} \right)\times 100\] \[=2\times \frac{1}{100}\times 100\] \[=2%\]
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