A) \[{{n}_{4}}\to {{n}_{1}}\]
B) \[{{n}_{2}}\to {{n}_{1}}\]
C) \[{{n}_{4}}\to {{n}_{2}}\]
D) \[{{n}_{3}}\to {{n}_{1}}\]
Correct Answer: A
Solution :
\[E=\frac{hc}{\lambda }orE\propto \frac{1}{\lambda }\] Thus, a decrease in wavelength represents an increase in energy for \[{{n}_{4}}\to {{n}_{1}}\] transition. Greater the energy difference will follow lower wavelength. Thus, for \[{{n}_{4}}\to {{n}_{1}}\] transition, wavelength would be minimum.
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