A) ethyl but -1-enoate
B) ethyl but-2-enoate
C) ethyl prop-2-enoate
D) None of the above
Correct Answer: B
Solution :
\[\overset{4}{\mathop{C}}\,{{H}_{3}}=\underset{ethyl\,\,but\,\,2-enoate}{\mathop{\overset{3}{\mathop{CH}}\,=\overset{2}{\mathop{C}}\,H\overset{1}{\mathop{C}}\,OO{{C}_{2}}}}\,{{H}_{5}}\]
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