A) \[\frac{x}{m}=Kp\]
B) \[\frac{x}{m}=K{{p}^{n}}\]
C) \[\log \frac{x}{m}=K{{p}^{n}}\]
D) \[\log \frac{x}{m}=Kn\log p\]
Correct Answer: B
Solution :
Freundlich adsorption isotherm reaction is\[\frac{x}{m}=K{{p}^{n}}\]
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