A) \[La{{(OH)}_{3}}\]is less basic than\[Lu{{(OH)}_{3}}\]
B) In lanthanide series, ionic radius of Lu^ ion decreases
C) \[La\]is actually an element of transition series rather lanthanide
D) Atomic radius of\[Zr\]and\[Hf\]are same because of lanthanide contraction
Correct Answer: A
Solution :
As the size of the lanthanide ions decreases from\[L{{a}^{3+}}\]to\[L{{u}^{3+}}\], the covalent character of the hydroxides increases and hence, the basics strength decreases. Thus, \[La{{(OH)}_{3}}\] is most basic whereas\[Lu{{(OH)}_{3}}\]is least basic.
You need to login to perform this action.
You will be redirected in
3 sec
