RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    If anybody is rolling on surface, then its total energy will be

    A)  \[\frac{1}{2}m{{v}^{2}}\,+\,\frac{1}{2}I{{\omega }^{2}}\]   

    B)  \[\frac{1}{2}m{{v}^{2}}\,-\,\frac{G{{m}_{1}}{{m}_{2}}}{R}\]

    C)  \[\frac{1}{2}m{{v}^{2}}\,-\,\frac{1}{2}\,m{{R}^{2}}{{\omega }^{2}}\]

    D)  None of these

    Correct Answer: A

    Solution :

     Total kinetic energy = Linear kinetic energy + rotational kinetic energy \[=\frac{1}{2}m{{v}^{2}}+\frac{1}{2}I{{\omega }^{2}}\]


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