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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    A solution obtained on mixing 0.1 N, 50 mL \[HCl\]and 0.1 N, 50 mL\[NaOH\]. The value of pH of the solution will be

    A)  4               

    B)  6

    C)  8               

    D)  7

    Correct Answer: D

    Solution :

     \[HCl+NaOH\xrightarrow[{}]{{}}NaCl+{{H}_{2}}O\] Equivalent number of\[HCl=\frac{0.1\times 50}{1000}=0.005\] Equivalent number of\[NaOH\] \[=\frac{0.1\times 50}{1000}=0.005\] Equivalent of\[HCl=\]Equivalent of\[NaOH\] \[0.005\equiv 0.005\] Hence, solution is neutral ie.,\[pH=7\]


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