RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    If the frequency of sodium ion is\[5.09\times {{10}^{14}}{{s}^{-1}}\]then wavelength will be

    A)  5.89nm        

    B)  589 nm

    C)  58.9 nm        

    D)  5890 nm

    Correct Answer: B

    Solution :

     Wavelength \[(\lambda )=\frac{velocity\text{ }of\text{ }light\text{ }(c)}{frequency\text{ }(v)}\] \[\lambda ==\frac{3\times {{10}^{8}}m/s}{5.09\times {{10}^{14}}{{s}^{-1}}}\] \[=5.89\times {{10}^{-7}}m\] \[=589nm\]


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