A) \[16\times {{10}^{-28}}kg\]
B) \[2.16\times {{10}^{-22}}kg\]
C) \[3.46\times {{10}^{-28}}kg\]
D) \[7.3\times {{10}^{-26}}kg\]
Correct Answer: D
Solution :
1 mole \[C{{O}_{2}}=44\,u\] \[\because \] \[1u=\frac{1}{6.023\times {{10}^{23}}}g\] \[44u=\frac{44\times {{10}^{-3}}}{6.023\times {{10}^{23}}}g\] \[=7.30\times {{10}^{-26}}kg\]
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