A) \[B{{r}_{2}}+KOH\]
B) \[Na+{{C}_{2}}{{H}_{5}}OH\]
C) \[LiAl{{H}_{4}}\]
D) \[AlC{{l}_{3}}\]
Correct Answer: A
Solution :
\[C{{H}_{3}}-C{{H}_{2}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,N{{H}_{2}}+B{{r}_{2}}+4KOH\xrightarrow[{}]{{}}\] \[C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}+{{K}_{2}}C{{O}_{3}}+2KBr+2{{H}_{2}}O\] This is Hofmann bromamide reaction.
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