A) \[{{C}_{2}}{{H}_{5}}OH\]
B) \[C{{H}_{3}}CHO\]
C) \[C{{H}_{3}}COOH\]
D) \[C{{H}_{3}}-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,-O-{{C}_{2}}{{H}_{5}}\]
Correct Answer: A
Solution :
\[C{{H}_{3}}-Mg-X+H-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,-H\xrightarrow[{}]{{}}\] \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OMgX \end{smallmatrix}}{\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}}\,-H\xrightarrow[{}]{{{H}_{2}}O}\underset{\begin{smallmatrix} primary \\ alcohol \end{smallmatrix}}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,\]
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