A) \[NH_{4}^{+}\]
B) \[N{{H}_{4}}OH\]
C) \[N{{H}_{3}}\]
D) \[{{N}_{2}}{{O}_{4}}\]
Correct Answer: C
Solution :
Conjugated acid of\[NH_{2}^{-}\]is\[N{{H}_{3}}\]. \[\underset{base}{\mathop{NH_{2}^{-}}}\,+{{H}^{+}}\xrightarrow[{}]{{}}\underset{conjugated\text{ }acid}{\mathop{N{{H}_{3}}}}\,\]
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