RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    Tangent and normal at any point P of the parabola meet the axes at T and G respectively, then

    A)  \[ST=SG.SP\]     

    B)  \[ST\ne SG=SP\]

    C)  \[ST=SG\ne SP\]    

    D)  \[ST=SG=SP\]

    Correct Answer: D

    Solution :

     Let a point\[P(a{{t}^{2}},2at)\]on the parabola \[{{y}^{2}}=4ax\] on which the equations of tangent and normal are\[ty=x+a{{t}^{2}}\] and \[y=-tx+2at+a{{t}^{3}}\]respectively. Since, tangent and normal meet the\[x-\]axis at T and G respectively. Therefore, coordinates of T and G are\[(-a{{t}^{2}},0)\]and\[(2a+a{{t}^{2}},0)\]respectively. By the definition of the parabola, \[SP=PM=a+a{{t}^{2}}\] \[SG=VG-VS\] \[=2a+a{{t}^{2}}-a=a+a{{t}^{2}}\] and       \[ST=VS+VT=a+a{{t}^{2}}\] Thus,        \[SP=SG=ST\]


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