A) \[8.85\,\times \,{{10}^{-12}}{{C}^{2}}/N-{{m}^{2}}\]
B) \[8.85\,\times \,{{10}^{-12}}\,Fermi\]
C) \[9\,\times \,{{10}^{-13}}\,{{C}^{2}}/N-{{m}^{2}}\]
D) \[9\,\times \,{{10}^{-13}}\,Fermi\]
Correct Answer: A
Solution :
\[\frac{1}{4\pi {{\varepsilon }_{0}}}=9\times {{10}^{9}}N{{m}^{2}}/C\] \[\therefore \] \[{{\varepsilon }_{0}}=\frac{1}{9\times {{10}^{9}}\times 4\pi }{{C}^{2}}/N-{{m}^{2}}\] \[=8.85\times {{10}^{-12}}{{C}^{2}}/N-{{m}^{2}}\]
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