RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    \[\underset{x\to 0}{\mathop{\lim }}\,\frac{x({{5}^{x}}-1)}{1-\cos x}\]is equal to

    A)  \[4\text{ }log\text{ }5\]           

    B)  \[2\text{ }log\text{ }5\]

    C)  \[\frac{1}{2}log\text{ }5\]            

    D)  None of these

    Correct Answer: B

    Solution :

     \[\underset{x\to 0}{\mathop{\lim }}\,\frac{x({{5}^{x}}-1)}{1-\cos x}\] \[=\underset{x\to 0}{\mathop{\lim }}\,\frac{x\left[ 1+x\log +\frac{{{x}^{2}}}{2!}{{(\log 5)}^{2}}+....-1 \right]}{1-\left( 1-\frac{{{x}^{2}}}{2!}+\frac{{{x}^{4}}}{4!}-.... \right)}\] \[=\underset{x\to 0}{\mathop{\lim }}\,\frac{\frac{{{x}^{2}}}{2!}[2\log 5+x{{(\log 5)}^{2}}+....]}{\frac{{{x}^{2}}}{2!}\left( 1-\frac{{{x}^{2}}}{12}+.... \right)}\] \[=2\log 5\]


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