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  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    If the temperature of gas increases from\[27{}^\circ C\]to \[927{}^\circ C,\]the KE will be

    A)  double          

    B)  half

    C)  one-fourth       

    D)  four times

    Correct Answer: D

    Solution :

     \[E\propto T\] \[\Rightarrow \] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{27+273}{927+273}=\frac{300}{1200}=\frac{1}{4}\] \[\Rightarrow \] \[{{E}_{2}}=4{{E}_{1}}\]


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