A) 100
B) 16
C) 12
D) 14
Correct Answer: A
Solution :
Number of triangles made by 10 points\[{{=}^{10}}{{C}_{3}}\] but 6 points are collinear \[\therefore \]Required number of triangles \[{{=}^{10}}{{C}_{3}}{{-}^{6}}{{C}_{3}}\] \[=\frac{1C\times 9\times 8}{3\times 2\times 1}-\frac{6\times 5\times 4}{3\times 2\times 1}\] \[=10\times 3\times 4-2\times 5\times 2\] \[=120-20\] \[=100\]
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