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  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    If\[A=\left[ \begin{matrix}    1 & -2 & 1  \\    2 & 1 & 3  \\ \end{matrix} \right]\]and\[B=\left[ \begin{matrix}    2 & 1  \\    3 & 2  \\    1 & 1  \\ \end{matrix} \right],\]then\[{{(AB)}^{T}}\]is equal to

    A)  \[{{A}^{T}}{{B}^{T}}\]

    B)  \[{{B}^{T}}{{A}^{T}}\]

    C)  \[{{(AB)}^{-1}}\]

    D)  \[A.B\]

    Correct Answer: B

    Solution :

     We know by the property of transpose, \[{{(AB)}^{T}}={{B}^{T}}{{A}^{T}}\] \[\therefore \] For the given matrices A and B above condition is true.


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