A) (1, 2)
B) \[(-3,-4)\]
C) (2, 0)
D) \[(-1,2)\]
Correct Answer: A
Solution :
Three vertices of the parallelogram are \[A(-1,-2),B(1,0),C(3,4)\] Let the fourth vertex be \[D(x,y)\] We know that, diagonals of parallelogram cut each other at mid point. \[\therefore \] \[\frac{-1+3}{2}=\frac{1+x}{2}\] \[\Rightarrow \] \[x=2-1\] \[\Rightarrow \] \[x=1\] and \[\frac{-2+4}{2}=\frac{0+y}{2}\] \[\Rightarrow \] \[y=2\] Hence, the fourth vertex is (1, 2).You need to login to perform this action.
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