A) \[v{{H}_{2}}=4{{v}_{O2}}\]
B) \[{{v}_{O2}}=4{{V}_{H2}}\]
C) \[{{v}_{O2}}=2{{v}_{H2}}\]
D) \[{{v}_{H2}}=2{{v}_{O2}}\]
Correct Answer: A
Solution :
\[v=\sqrt{\frac{3RT}{M}}\] \[\Rightarrow \] \[v\propto \frac{1}{\sqrt{M}}\] \[\therefore \] \[\frac{{{v}_{{{O}_{2}}}}}{{{v}_{{{H}_{2}}}}}=\sqrt{\left( \frac{{{M}_{{{H}_{2}}}}}{{{M}_{{{O}_{2}}}}} \right)}=\sqrt{\frac{2}{32}}=\frac{1}{4}\] \[\Rightarrow \] \[{{v}_{{{H}_{2}}}}=4{{v}_{{{O}_{2}}}}\]
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