A) 6
B) 4
C) 7
D) 3
Correct Answer: A
Solution :
Let the oxidation number of Cr is\[x\]in\[{{K}_{2}}C{{r}_{2}}{{O}_{7}}.\] \[2+(1)+2x+7(-2)=0\] \[2+2x-14=0\] \[2x-12=0\] \[2x=12\] \[x=+6\]You need to login to perform this action.
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