A) \[8\times {{10}^{-11}}C\]
B) \[8\times {{10}^{11}}C\]
C) \[4\times {{10}^{11}}C\]
D) \[4\times {{10}^{-11}}C\]
Correct Answer: A
Solution :
\[E=2V/m\] \[\Rightarrow \] \[\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{q}{{{r}_{2}}}=2\] \[\therefore \] \[q=8\pi {{\varepsilon }_{0}}{{r}^{2}}\] \[q=\frac{2}{9\times {{10}^{9}}}\times {{(60\times {{10}^{-2}})}^{2}}\] \[=8\times {{10}^{-11}}C\]
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