A) nG
B) (n-1)G
C) \[\frac{G}{n}\]
D) \[\frac{G}{(n-1)}\]
Correct Answer: B
Solution :
\[V={{I}_{g}}(G+R)\] Current in ammeter, \[{{I}_{g}}=\frac{V}{G}\] \[\therefore \] \[\frac{nV}{{{I}_{g}}}=R+G\] \[\Rightarrow \] \[R=\frac{nV}{{{I}_{g}}}-G=G\frac{nV}{V}-G\] \[=G(n-1)\]You need to login to perform this action.
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