RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    Light is incident normally on diffraction grating through which the first order, diffraction is seen\[32{}^\circ \]. The second order diffraction will be seen at

    A)  \[48{}^\circ \]

    B)  \[64{}^\circ \]

    C)  \[80{}^\circ \]

    D)  There is no second order diffraction in this case

    Correct Answer: D

    Solution :

     For grating \[(e+d)\text{ }sin\theta =n\lambda \] where\[(e+d)=\]grating element \[\sin {{\theta }_{n}}=\frac{n\lambda }{(e+d)}\] For\[n=1\] \[\sin \theta =\frac{\lambda }{e+d}=\sin 32{}^\circ \] Here the value of\[\sin {{\theta }_{1}}\]is more than 0.5. Now \[\sin {{\theta }_{2}}\]will be more than\[2\times 0.5\]. This is impossible.


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