A) 1 : 1
B) 3 : 1
C) 1 : 3
D) 1 : 9
Correct Answer: B
Solution :
\[\frac{{{I}_{\max }}}{{{I}_{\min }}}=\frac{{{({{a}_{1}}+{{a}_{2}})}^{2}}}{({{a}_{1}}-{{a}_{2}})}=\frac{4}{1}\Rightarrow \frac{{{a}_{1}}}{{{a}_{2}}}=\frac{3}{1}\]
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