A) 1800 J
B) 1000 J
C) 2000 J
D) 1600 J
Correct Answer: D
Solution :
\[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}=1-\frac{300}{600}=\frac{1}{2}\] Now, \[\eta =\frac{Output\text{ }work}{Input\text{ }heat}\] Input heat\[=\frac{800}{1/2}\] \[=1600J/rev\]
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