A) \[{{2}^{2.3}}\]atm
B) 4 atm
C) 6 atm
D) None of these
Correct Answer: A
Solution :
Poisson's ratio \[p{{V}^{\gamma }}=\]constant \[{{p}_{1}}{{V}_{1}}^{\gamma }={{p}_{2}}{{V}_{2}}^{\gamma }\] \[2V={{p}_{2}}{{\left( \frac{V}{2} \right)}^{\gamma }}\] \[{{p}_{2}}={{2}^{1+\gamma }}={{2}^{2.3}}\]atmYou need to login to perform this action.
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