A) \[pH=p{{K}_{a}}+\log \frac{[salt]}{[acid]}\]
B) \[p{{K}_{a}}=pH-\log \frac{[salt]}{[acid]}\]
C) \[pH=p{{K}_{a}}-\log \frac{[salt]}{[acid]}\]
D) \[p{{K}_{a}}=pH+\log \frac{[salt]}{[acid]}\]
Correct Answer: A
Solution :
Henderson's equation is as \[pH=p{{K}_{a}}+\log \frac{[salt]}{[acid]}\]
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