A) \[C{{H}_{4}}\]
B) \[{{C}_{2}}{{H}_{2}}\]
C) \[{{C}_{2}}{{H}_{6}}\]
D) \[{{C}_{2}}{{H}_{4}}\]
Correct Answer: B
Solution :
\[\underset{iodoform}{\mathop{2CH{{I}_{3}}}}\,+\underset{silver}{\mathop{6Ag}}\,\xrightarrow[{}]{{}}\underset{acetylene}{\mathop{{{C}_{2}}{{H}_{2}}}}\,+6AgI\]
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