A) increases 100 times
B) decreases 100 times
C) decreases 1000 times
D) increases 1000 times
Correct Answer: B
Solution :
\[[{{H}^{+}}]={{10}^{-pH}}\] If \[pH=2\]then \[{{[{{H}^{+}}]}_{1}}={{10}^{-2}}\] \[pH=2\]then\[{{[{{H}^{+}}]}_{2}}={{10}^{-4}}\] \[\frac{{{[{{H}^{+}}]}_{2}}}{{{[{{H}^{+}}]}_{1}}}=\frac{{{10}^{-4}}}{{{10}^{-2}}}={{10}^{-2}}\] Hence, concentration will decrease 100 times.
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