question_answer

\[{{K}_{2}}C{{r}_{2}}{{O}_{3}}\xrightarrow[{}]{{}}C{{r}^{3+}}\] In the above process, oxidation number of Cr changes to

A)  from 6 to 3       

B)  from -6 to 3

C)  from + 3 to 0     

D)  from + 6 to 0

Correct Answer: A

Solution :

  \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\xrightarrow[{}]{reduction}C{{r}^{3+}}\] Oxidation number of Cr changes from +6 to +3.