RAJASTHAN ­ PET Rajasthan PET Solved Paper-2002

  • question_answer
    The ratio of translational kinetic energy to the total kinetic energy for rolling motion of solid sphere without sliding will be

    A)  \[\frac{2}{7}\]             

    B)  \[\frac{7}{2}\]

    C)  \[\frac{5}{7}\]            

    D)  \[\frac{7}{5}\]

    Correct Answer: C

    Solution :

     \[\frac{{{K}_{translational}}}{{{K}_{total}}}=\frac{\frac{1}{2}m{{v}^{2}}}{\frac{1}{2}I{{\omega }^{2}}+\frac{1}{2}m{{v}^{2}}}\] \[=\frac{\frac{1}{2}m{{v}^{2}}}{\frac{1}{2}.\frac{2}{5}m{{R}^{2}}{{\omega }^{2}}+\frac{1}{2}m{{v}^{2}}}=\frac{\frac{1}{2}}{\frac{7}{10}}=\frac{5}{7}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner