RAJASTHAN ­ PET Rajasthan PET Solved Paper-2002

  • question_answer
    In the following reaction product will be \[C{{H}_{3}}-\underset{\begin{smallmatrix}  || \\  O \end{smallmatrix}}{\mathop{C}}\,-ON{{H}_{4}}\xrightarrow[{}]{{{P}_{4}}{{O}_{10}}}Product\]

    A)  \[C{{H}_{3}}-C=N\]    

    B)  \[C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}\]

    C)  \[C{{H}_{3}}-C-N{{H}_{2}}\]  

    D)  \[C{{H}_{3}}COOH\]

    Correct Answer: A

    Solution :

     \[{{P}_{4}}{{O}_{10}}\] acts as dehydrating agent. \[\underset{ammonium\text{ }acetate}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix}  || \\  O \end{smallmatrix}}{\mathop{C}}\,-ON{{H}_{4}}}}\,\xrightarrow[{}]{{{P}_{4}}{{O}_{10}}}\underset{methyl\text{ }cyanide}{\mathop{C{{H}_{3}}-C\equiv N}}\,+2{{H}_{2}}O\]


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