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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2002

  • question_answer
    Oxidation number of\['N'\] in\[{{N}_{3}}H\]is

    A)  \[-\frac{1}{3}\]            

    B)  \[+3\]

    C)  0               

    D)  \[-3\]

    Correct Answer: A

    Solution :

     Let the oxidation number of N is\[x\]in\[{{N}_{3}}H\] (hydrazoic acid) \[3x+1=0\] \[3x=-1\] \[x=-\frac{1}{3}\]


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