A) Both at same time
B) Hollow cylinder
C) Solid cylinder
D) Which has more density
Correct Answer: C
Solution :
Moment of inertia about geometrical axis For hollow cylinder\[({{I}_{H}})=M{{R}^{2}}\] For solid cylinder\[({{I}_{s}})=1/2M{{R}^{2}}\] As no external torque is acting. \[\therefore \] \[\tau =I\omega =\]constant As\[{{I}_{s}}<{{I}_{H}}\]therefore\[{{\omega }_{s}}>{{\omega }_{H}}\] Therefore solid cylinder will reach first at bottom.
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