A) \[{{u}^{2}}{{\sin }^{2}}\theta /g\]
B) \[\frac{2{{u}^{2}}\sin \theta \cos \theta }{g}\]
C) \[\frac{{{u}^{2}}\sin 2\theta }{2g}\]
D) \[\frac{{{u}^{2}}\cos 2\theta }{g}\]
Correct Answer: B
Solution :
\[R=\frac{{{u}^{2}}\sin 2\theta }{g}=\frac{2{{u}^{2}}\sin \theta \cos \theta }{g}\]
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