A) \[\frac{1}{36}\]
B) \[\frac{11}{36}\]
C) \[\frac{2}{36}\]
D) \[\frac{1}{36}\]
Correct Answer: D
Solution :
Number of ways to get 7 as the sum on the two dice {(1, 6),(2, 5),(3, 4), (4, 3), (5, 2), (6, 1)} \[\therefore \] Required probability \[=\frac{6}{36}=\frac{1}{6}\]
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