A) \[\frac{1}{4}\]
B) \[{{\left( \frac{1}{2} \right)}^{n}}\]
C) \[\frac{1}{2}\]
D) \[\frac{3}{8}\]
Correct Answer: C
Solution :
\[\therefore \]Required probability \[{{=}^{n}}{{C}_{1}}{{\left( \frac{1}{2} \right)}^{1}}{{\left( \frac{1}{2} \right)}^{n-1}}{{+}^{n}}{{C}_{3}}{{\left( \frac{1}{2} \right)}^{3}}{{\left( \frac{1}{2} \right)}^{n-3}}+...\] \[={{\left( \frac{1}{2} \right)}^{n}}{{.2}^{n-1}}=\frac{1}{2}\]
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