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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2002

  • question_answer
    The two charges 7 \[\mu \] C and - 5\[\mu \] C are placed at some distance from each other. They experience a force F. If each of them is given and additional charge of - 2\[\mu \]C, the new force of attraction will be

    A)  F               

    B)  2F

    C)  F/2             

    D)  zero

    Correct Answer: A

    Solution :

     \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{(7)(-5)\times {{10}^{-12}}}{{{r}^{2}}}N\] Again \[F'=\frac{1}{4\pi {{\varepsilon }_{0}}}\] \[=\frac{(7-2)(-5-2)\times {{10}^{-12}}}{{{r}^{2}}}N\] \[F'=F\]


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