A) 400
B) 40
C) 540
D) None of these
Correct Answer: B
Solution :
\[W=p\Delta V\] \[=1\times {{10}^{5}}[1671\times {{10}^{-6}}-1\times {{10}^{-6}}]\] \[=167J\] \[=\frac{167}{4.18}cal\] \[=40\,cal\]You need to login to perform this action.
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