2. Solved Papers
  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2002

  • question_answer
    Burning 1 g coal gives 2 kcal useful energy. For 1 kWh, the quantity of coal needed will be

    A)  \[9kg\]

    B)  \[\frac{4}{3}kg\]

    C)  \[\frac{3}{7}kg\]

    D)  \[\frac{3}{14}kg\]  

    Correct Answer: C

    Solution :

     Energy needed\[1\text{ }kWh=60\times 60\text{ }kJ\] \[=\frac{3600}{4.18}\] kcal The quantity of mass\[=\frac{3600}{4.18}\times \frac{1}{2}\] \[=430.6\text{ }g\] \[=\frac{3}{7}kg\]


You need to login to perform this action.
You will be redirected in 3 sec spinner