RAJASTHAN ­ PET Rajasthan PET Solved Paper-2002

  • question_answer
    The positive charged ball is suspended by thread of silk. If we place a positive charge\[{{q}_{0}}\]at one point and measure the\[F/{{q}_{0}},\]then this can say that electric field E

    A)  \[>\frac{F}{{{q}_{0}}}\]

    B)  \[=\frac{F}{{{q}_{0}}}\]

    C)  \[=\frac{F}{{{q}_{0}}}\]

    D)  \[Can't\,be\,measured\]

    Correct Answer: A

    Solution :

     Electric field, \[E>\frac{F}{{{q}_{0}}}\]


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